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7v^2-38v+15=0
a = 7; b = -38; c = +15;
Δ = b2-4ac
Δ = -382-4·7·15
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-32}{2*7}=\frac{6}{14} =3/7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+32}{2*7}=\frac{70}{14} =5 $
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